Answer : Option:- C
A beam having more than two support is called as continuous beam.
Answer : Option:- A
Deflection of simply supported is inversely proportional to area moment of inertia.
Answer : Option:- A
Given:
Torque= T = 1600 Nm
Diameter = D= 60mm = 0.06m
Thus,
The maximum shear stress is,
=16T/(πD³)
=(16 *1600)/(π*0.06³)
=37.72 Mpa
Answer : Option:- C
Polar moment of inertia for circular shaft of diameter D is Ip=πd^4/32
The maximum shear stress is given by,
{ τ/(D/2) } = T/Ip
τ(max)= 16T/πD³
Answer : Option:- D
The relation between E, K and G is:
9/E = 1/K = 3/G
Answer : Option:- A
Given:
Poisson’s ratio of a material μ= 0.5
We have relation
G=E / (2(1 + μ))
(where G=shear modulus , E= elastic modulus)
put μ=0.5, we get
3G=E i.e. E=3G;
Thus, elastic modulus for the material is three times its shear modulus
Answer : Option:- C
In a beam of uniform strength, the maximum bending stress is the same throughout the length.
Answer : Option:- C
The Mohr’s circle will be a circle with radius τ and center at (0,0). It is a case of pure shear, like in torsional load in the shafts.