Q.
For a circular shaft of diameter d subjected to torque T, the maximum value of the shear stress is
Answer & Explanation
Polar moment of inertia for circular shaft of diameter D is Ip=πd^4/32
The maximum shear stress is given by,
{ τ/(D/2) } = T/Ip
τ(max)= 16T/πD³
Thus correct option is: C.